August 25, 2018
BY Help Me Our Always0
Comments
Showing posts with label C Programs. Show all posts
Showing posts with label C Programs. Show all posts
Saturday, August 25, 2018
Sunday, June 24, 2018
C Programs
C Programs- Switch Case
C Program Simple Calculator Using Switch Case(switch case example)
June 24, 2018
BY Help Me Our Always0
Comments
#include<stdio.h>
main ()
{
int menu, add, sub, mult, quit, num1, num2;
float dvd,Num1,Num2;// Here Num1 and Num2 is declared for Division operaion
printf ("=======================================\n");
printf ("Simple Calculator for Addition And Subtraction");
printf ("=======================================\n");
printf ("1.Add\n");
printf ("2.Sub\n");
printf ("3.Multiplication\n");
printf ("4.Division\n");
printf ("5.Quit\n");
printf ("Please Select what do you want?\n");
scanf ("%d", &menu);
switch (menu)
{
case 1:
printf ("Enter Two Numbers:\n");
scanf ("%d %d", &num1, &num2);
add = num1 + num2;
printf ("Addition =%d", add);
break;
case 2:
printf ("Enter Two Numbers:\n");
scanf ("%d %d", &num1, &num2);
sub = num1 - num2;
printf ("Subtraction =%d\n", sub);
break;
case 3:
printf ("Enter Two Numbers:\n");
scanf ("%d %d", &num1, &num2);
mult = num1 * num2;
printf ("Multiplication =%d\n", mult);
break;
case 4:
printf ("Enter Two Numbers:\n");
scanf ("%f %f", &Num1, &Num2);
dvd = Num1 / Num2;
printf ("Division =%.2f", dvd);
break;
case 5:
printf ("Program terminated!");
break;
default:
printf ("Wrong Input!");}
return 0;
}
main ()
{
int menu, add, sub, mult, quit, num1, num2;
float dvd,Num1,Num2;// Here Num1 and Num2 is declared for Division operaion
printf ("=======================================\n");
printf ("Simple Calculator for Addition And Subtraction");
printf ("=======================================\n");
printf ("1.Add\n");
printf ("2.Sub\n");
printf ("3.Multiplication\n");
printf ("4.Division\n");
printf ("5.Quit\n");
printf ("Please Select what do you want?\n");
scanf ("%d", &menu);
switch (menu)
{
case 1:
printf ("Enter Two Numbers:\n");
scanf ("%d %d", &num1, &num2);
add = num1 + num2;
printf ("Addition =%d", add);
break;
case 2:
printf ("Enter Two Numbers:\n");
scanf ("%d %d", &num1, &num2);
sub = num1 - num2;
printf ("Subtraction =%d\n", sub);
break;
case 3:
printf ("Enter Two Numbers:\n");
scanf ("%d %d", &num1, &num2);
mult = num1 * num2;
printf ("Multiplication =%d\n", mult);
break;
case 4:
printf ("Enter Two Numbers:\n");
scanf ("%f %f", &Num1, &Num2);
dvd = Num1 / Num2;
printf ("Division =%.2f", dvd);
break;
case 5:
printf ("Program terminated!");
break;
default:
printf ("Wrong Input!");}
return 0;
}
Output:
Friday, June 22, 2018
C Programs
C Programs- Switch Case
C program Simple Calculator Of Addition or Subtraction using Switch Case
June 22, 2018
BY Help Me Our Always0
Comments
Source Code
#include<stdio.h>
int
main ()
{
int menu, add, sub, quit, num1, num2;
printf ("======================================================\n");
printf ("Simple Calculator for Addition And Subtraction");
printf ("======================================================\n");
printf ("1.Add\n");
printf ("2.Sub\n");
printf ("3.Quit\n");
printf ("Please Select what do you want?\n");
scanf ("%d", &menu);
switch (menu)
{
case 1:
printf ("Enter Two Numbers:\n");
scanf ("%d %d", &num1, &num2);
add = num1 + num2;
printf ("Addition =%d", add);
break;
case 2:
printf ("Enter Two Numbers:\n");
scanf ("%d %d", &num1, &num2);
sub = num1 - num2;
printf ("Subtraction =%d\n", sub);
break;
case 3:
printf("Program terminated!");
break;
default:
printf ("Wrong Input!");
}
return 0;
}
Output:
C Programs
C Programs- Switch Case
C Switch Case Program (What Do You Want to Drink?) Simple Example for bignners
June 22, 2018
BY Help Me Our Always0
Comments
Source Code
#include<stdio.h>main ()
{
int drink;
printf ("Hello!Sir\n");
printf ("What would you like to drink?\n");
printf ("1.Tea\n");
printf ("2. Coffe\n");
printf ("Please Select (1/2):\n");
scanf ("%d", &drink);
switch (drink)
{
case 1:
printf ("Tea! ok Sir, i will be right back ", drink);
break;
case 2:
printf ("Coffe! ok Sir, i will be right back ", drink);
break;
}
return 0;
}
Output
Friday, June 15, 2018
Wednesday, June 13, 2018
C Programs
C Programs- Switch Case
C Program To Check Whether it Is Vowel or Constant (Switch Case Example)
June 13, 2018
BY Help Me Our Always0
Comments
//Write a C program TO chEck WheatHer It iS VoWel Or CoNsTant
#include<stdio.h>
main()
{
char ch;
printf("Enter any character:\n");
scanf("%c",&ch);
switch(ch)
{
case 'a': case 'A' :
printf("Its VOwel Baby!");
break;
case 'e': case 'E' :
printf("Its VOwel Baby!");
break;
case 'i': case 'I' :
printf("Its VOwel Baby!");
break;
case 'o': case 'O' :
printf("Its VOwel Baby!");
break;
case 'u': case 'U' :
printf("Its VOwel Baby!");
break;
default:
printf("Its Constant Baby!");
}
return 0;
}
Output:
#include<stdio.h>
main()
{
char ch;
printf("Enter any character:\n");
scanf("%c",&ch);
switch(ch)
{
case 'a': case 'A' :
printf("Its VOwel Baby!");
break;
case 'e': case 'E' :
printf("Its VOwel Baby!");
break;
case 'i': case 'I' :
printf("Its VOwel Baby!");
break;
case 'o': case 'O' :
printf("Its VOwel Baby!");
break;
case 'u': case 'U' :
printf("Its VOwel Baby!");
break;
default:
printf("Its Constant Baby!");
}
return 0;
}
Output:
C Programs
C Programs- Switch Case
Check Whether The Number Is Positive, Negative Or Zero With Switch Statement
June 13, 2018
BY Help Me Our Always0
Comments
#include<stdio.h>
main()
{
int num;
printf("Enter any Number To Check It is Positive or Negative:\n");
scanf("%d",&num);
switch(num>0)
{
case 1:
printf("%d is positive number",num);
break;
case 0:
switch(num<0)
{
case 1:
printf("%d is negative number",num);
break;
case 0:
printf("%d is zero",num);
break;
}
break;
}
return 0;
}
main()
{
int num;
printf("Enter any Number To Check It is Positive or Negative:\n");
scanf("%d",&num);
switch(num>0)
{
case 1:
printf("%d is positive number",num);
break;
case 0:
switch(num<0)
{
case 1:
printf("%d is negative number",num);
break;
case 0:
printf("%d is zero",num);
break;
}
break;
}
return 0;
}
Sunday, June 10, 2018
June 10, 2018
BY Help Me Our Always1
Comments
Here you can find the source code of ATM Machine Program Transaction In C language by HelpMeOutAlways.
ATM Machine Program Source Code
#include <stdio.h>
unsigned long int amount = 50000, depositS;
//Number Of Notes Available in The ATM Machine, down below statements
unsigned long int FiveThousandNotes = 50;
unsigned long int ThousandNotes = 50;
unsigned long int FiveHundredNotes = 50;
unsigned long int OneHundredNotes = 50;
unsigned long int TenNotes = 50;
unsigned long int fiftyNotes = 50;
unsigned long int withdrawAmount;
unsigned long int totalMoney;
unsigned long int fivethousand = 0, thousand = 0, fiveHundred =
0, oneHundred = 0, fifty = 0, ten = 0;
int choice, pin, k;
char transaction = 'y';
main ()
{
while (pin != 1520)
{
printf ("ENTER YOUR FOUR DIGIT PIN NUM:"); //User will Enter His Four Digit Pin Code
scanf ("%d", &pin); // REads OutPut
if (pin != 1520) /// IF It is Not The COrrect Pin
printf ("WRONG PASSWORD! TRY AGAIN\n");
}
do // It Will Once Print All the Statements Given Below
{
printf ("********Welcome to ATM Service**************\n");
printf ("1. Check Balance\n");
printf ("2. Withdraw Cash\n");
printf ("3. Deposit Cash\n");
printf ("4. Quit\n");
printf ("******************?**************************?*\n\n");
printf ("Enter your choice: "); // Chooes One of The Option
scanf ("%d", &choice); //Read The input
switch (choice)
{
case 1: // Check Balance
printf ("\n YOUR BALANCE IN Rs : %lu ", amount);
break;
case 2: // To widthdraw Money
printf ("Enter the amount in multiple of 10:"); // Enter money more than 100 in multiples
scanf ("%lu", &withdrawAmount);
if (withdrawAmount < amount)
{
amount = amount - withdrawAmount;
printf ("\nYour balance is Rs: %lu \n", amount);
}
if (withdrawAmount % 10 != 0) // If not in Multip
{
printf ("Invalid amount\n");
return 0;
}
totalMoney =
ThousandNotes * 1000 + FiveHundredNotes * 500 +
OneHundredNotes * 100 + fiftyNotes * 50 + TenNotes * 10;
if (withdrawAmount > totalMoney)
{
printf ("Sorry,Insufficient money\n");
return 0;
}
fivethousand = withdrawAmount / 5000;
if (fivethousand > FiveThousandNotes)
fivethousand = FiveThousandNotes;
withdrawAmount = withdrawAmount - fivethousand * 5000;
thousand = withdrawAmount / 1000;
if (thousand > ThousandNotes)
thousand = ThousandNotes;
withdrawAmount = withdrawAmount - thousand * 1000;
fiveHundred = withdrawAmount / 500;
if (fiveHundred > FiveHundredNotes)
fiveHundred = FiveHundredNotes;
withdrawAmount = withdrawAmount - fiveHundred * 500;
if (withdrawAmount > 0)
oneHundred=withdrawAmount/100;
if (oneHundred > OneHundredNotes)
oneHundred = OneHundredNotes;
withdrawAmount = withdrawAmount - oneHundred * 100;
if (withdrawAmount > 0)
fifty=withdrawAmount/50;
if (fifty > fiftyNotes)
fifty = fiftyNotes;
withdrawAmount = withdrawAmount - fifty * 50;
if (withdrawAmount > 0)
ten = withdrawAmount / 10;
if (ten > TenNotes)
ten = TenNotes;
withdrawAmount = withdrawAmount - ten * 10;
printf ("Total 5000 note:%lu\n", fivethousand);
printf ("Total 1000 note:%lu\n", thousand);
printf ("Total 500 note:%lu\n", fiveHundred);
printf ("Total 100 note:%lu\n", oneHundred);
printf ("Total 50 notes:%lu\n", fifty);
printf ("Total 10 notes:%lu\n", ten);
break;
case 3:
printf ("\n ENTER THE AMOUNT TO DEPOSIT:");
scanf ("%lu", &depositS);
amount = amount + depositS;
printf ("YOUR BALANCE IS %lu", amount);
break;
case 4:
printf ("\n THANK U USING ATM");
break;
default:
printf ("\n INVALID CHOICE");
}
printf ("\n\n\n DO U WISH TO HAVE ANOTHER TRANSCATION?(y/n): \n");
fflush (stdin); //It make a wide Space Between the Line
scanf ("%c", &transaction);
if (transaction == 'n' || transaction == 'N')
k = 1;
}
while (!k);
printf ("\n\n THANKS FOR USING OUT ATM SERVICE");
return 0;
}
I hope that this ATM Program In C language has helped you to understand how ATM Machine works.
ATM Machine Program Source Code
#include <stdio.h>unsigned long int amount = 50000, depositS;
//Number Of Notes Available in The ATM Machine, down below statements
unsigned long int FiveThousandNotes = 50;
unsigned long int ThousandNotes = 50;
unsigned long int FiveHundredNotes = 50;
unsigned long int OneHundredNotes = 50;
unsigned long int TenNotes = 50;
unsigned long int fiftyNotes = 50;
unsigned long int withdrawAmount;
unsigned long int totalMoney;
unsigned long int fivethousand = 0, thousand = 0, fiveHundred =
0, oneHundred = 0, fifty = 0, ten = 0;
int choice, pin, k;
char transaction = 'y';
main ()
{
while (pin != 1520)
{
printf ("ENTER YOUR FOUR DIGIT PIN NUM:"); //User will Enter His Four Digit Pin Code
scanf ("%d", &pin); // REads OutPut
if (pin != 1520) /// IF It is Not The COrrect Pin
printf ("WRONG PASSWORD! TRY AGAIN\n");
}
do // It Will Once Print All the Statements Given Below
{
printf ("********Welcome to ATM Service**************\n");
printf ("1. Check Balance\n");
printf ("2. Withdraw Cash\n");
printf ("3. Deposit Cash\n");
printf ("4. Quit\n");
printf ("******************?**************************?*\n\n");
printf ("Enter your choice: "); // Chooes One of The Option
scanf ("%d", &choice); //Read The input
switch (choice)
{
case 1: // Check Balance
printf ("\n YOUR BALANCE IN Rs : %lu ", amount);
break;
case 2: // To widthdraw Money
printf ("Enter the amount in multiple of 10:"); // Enter money more than 100 in multiples
scanf ("%lu", &withdrawAmount);
if (withdrawAmount < amount)
{
amount = amount - withdrawAmount;
printf ("\nYour balance is Rs: %lu \n", amount);
}
if (withdrawAmount % 10 != 0) // If not in Multip
{
printf ("Invalid amount\n");
return 0;
}
totalMoney =
ThousandNotes * 1000 + FiveHundredNotes * 500 +
OneHundredNotes * 100 + fiftyNotes * 50 + TenNotes * 10;
if (withdrawAmount > totalMoney)
{
printf ("Sorry,Insufficient money\n");
return 0;
}
fivethousand = withdrawAmount / 5000;
if (fivethousand > FiveThousandNotes)
fivethousand = FiveThousandNotes;
withdrawAmount = withdrawAmount - fivethousand * 5000;
thousand = withdrawAmount / 1000;
if (thousand > ThousandNotes)
thousand = ThousandNotes;
withdrawAmount = withdrawAmount - thousand * 1000;
fiveHundred = withdrawAmount / 500;
if (fiveHundred > FiveHundredNotes)
fiveHundred = FiveHundredNotes;
withdrawAmount = withdrawAmount - fiveHundred * 500;
if (withdrawAmount > 0)
oneHundred=withdrawAmount/100;
if (oneHundred > OneHundredNotes)
oneHundred = OneHundredNotes;
withdrawAmount = withdrawAmount - oneHundred * 100;
if (withdrawAmount > 0)
fifty=withdrawAmount/50;
if (fifty > fiftyNotes)
fifty = fiftyNotes;
withdrawAmount = withdrawAmount - fifty * 50;
if (withdrawAmount > 0)
ten = withdrawAmount / 10;
if (ten > TenNotes)
ten = TenNotes;
withdrawAmount = withdrawAmount - ten * 10;
printf ("Total 5000 note:%lu\n", fivethousand);
printf ("Total 1000 note:%lu\n", thousand);
printf ("Total 500 note:%lu\n", fiveHundred);
printf ("Total 100 note:%lu\n", oneHundred);
printf ("Total 50 notes:%lu\n", fifty);
printf ("Total 10 notes:%lu\n", ten);
break;
case 3:
printf ("\n ENTER THE AMOUNT TO DEPOSIT:");
scanf ("%lu", &depositS);
amount = amount + depositS;
printf ("YOUR BALANCE IS %lu", amount);
break;
case 4:
printf ("\n THANK U USING ATM");
break;
default:
printf ("\n INVALID CHOICE");
}
printf ("\n\n\n DO U WISH TO HAVE ANOTHER TRANSCATION?(y/n): \n");
fflush (stdin); //It make a wide Space Between the Line
scanf ("%c", &transaction);
if (transaction == 'n' || transaction == 'N')
k = 1;
}
while (!k);
printf ("\n\n THANKS FOR USING OUT ATM SERVICE");
return 0;
}
Outputs
I hope that this ATM Program In C language has helped you to understand how ATM Machine works.
Sunday, June 3, 2018
C Programs
C Programs If-else
C Program To Find Maximum Among Three Numbers(Integers) Using Nested if-else Statement
June 03, 2018
BY Help Me Our Always0
Comments
//find maximum number among three integers
#include<stdio.h>
main()
{
int n1,n2,n3,max; //Declaration of variables
printf("Enter any three integers:\n");
scanf("%d%d%d",&n1,&n2,&n3);// Read three numbers from user
if(n1>n2) //let(condition 1)
{
if(n1>n3)//let (condition 2)
{
max=n1;} //if condition 1 and 2 are true then n1 is maximum
else{
max=n3; //if condition 1 is true but condition 2 is not true then max=n3
}
}
else
{
if(n2>n3){//let (condition3) if condition1 and condition2 are both false then condition 3 will execute i.e max=2
max=n2;}
else
{max=n3;//if conditon 1,2,3 are false then max=n3
}
}
printf("maximun from above three integers is=%d",max);//Show the maximum number to the outside world
return 0;
}
#include<stdio.h>
main()
{
int n1,n2,n3,max; //Declaration of variables
printf("Enter any three integers:\n");
scanf("%d%d%d",&n1,&n2,&n3);// Read three numbers from user
if(n1>n2) //let(condition 1)
{
if(n1>n3)//let (condition 2)
{
max=n1;} //if condition 1 and 2 are true then n1 is maximum
else{
max=n3; //if condition 1 is true but condition 2 is not true then max=n3
}
}
else
{
if(n2>n3){//let (condition3) if condition1 and condition2 are both false then condition 3 will execute i.e max=2
max=n2;}
else
{max=n3;//if conditon 1,2,3 are false then max=n3
}
}
printf("maximun from above three integers is=%d",max);//Show the maximum number to the outside world
return 0;
}
Tuesday, May 29, 2018
May 29, 2018
BY Help Me Our Always0
Comments
May 29, 2018
BY Help Me Our Always0
Comments
May 29, 2018
BY Help Me Our Always0
Comments
//Multiplication Table oF desite
#include <stdio.h>
int main()
{
int n, i,start, range;
printf("Enter an integer: ");
scanf("%d",&n);
printf("Enter the Start: ");
scanf("%d", &start);
printf("Enter the range: ");
scanf("%d", &range);
for(i= start; i <= range; ++i)
{
printf("%d * %d = %d \n", n, i, n*i);
}
return 0;
}
Output Of Program
#include <stdio.h>
int main()
{
int n, i,start, range;
printf("Enter an integer: ");
scanf("%d",&n);
printf("Enter the Start: ");
scanf("%d", &start);
printf("Enter the range: ");
scanf("%d", &range);
for(i= start; i <= range; ++i)
{
printf("%d * %d = %d \n", n, i, n*i);
}
return 0;
}
Output Of Program